Question

solve this question

In a 3-digit number, sum of the digits is 9 and the units digit is twice the tens digit. On adding 99 to the
number, the digits are reversed. Find the number.​

Answer 1

Answer:

999999999 is the right answer

Answer 2

Answer:

Hmm...a 3-digit huh...□□□

□+□+□=9..

units digit is twice the tens digit..

□□□+99=□□□(reversed)...

so that's the question..hmmm....

I can only think of three,and they are:

108, 315, and 522.

Step-by-step explanation:

For 108, the digits obviously sum to 9, 1+0+8=91+0+8=9, reversing we get 801, adding 99 to get 900. The tens digit is then 0 and the units is 0, which is twice 0.

315 reversed is 513 and adding 99 we get 612. 2 is twice 1, so this works as a solution.

522 reversed is 225, adding 99 we get 624, 4 is twice 2, so again this works as a solution.