Question

solve this question in the attachment​

Answer 1

Question :-

A particle moves along x-axis as x=4(t−2)+a(t−2)²

Which of the following is true?

The initial velocity of particle is 4

the acceleration of particle is 2a

The particle is at origin at t=0

none of these

Answer :  B

Solution :

x=4(t−2)+a(t−2)2

At t=0,x=−8+4a=4a−8

v=dxdt=4+2a(t−2)

At t=0,v=4−4a=4(1−a)

But acceleration, a=d2xdt2=2a

Answer 2

Answer:

option (b) is true. systement......

= The acceleration of particle is 2a