Question

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Answer 1

Answer:

(3) IBl/2π

Explanation:

Considering an elemental length dL of the wire, the magnetic force F acting on the element is given by

F = idLB = iRdθB, as is clear from the figure.

The tension T developed in the wire is resolved into rectangular components T sin(dθ/2) and T cos(dθ/2) as indicated in the figure.

The magnetic force F is related to the tension T as

F = iRdθB = 2T sin(dθ/2)

Since dθ is a very small angle, sin(dθ/2) ≈ dθ/2

Therefore, the above equation gives T = iRB

But R = L /2π

Therefore, T = iBL /2π

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Answer 2

Answer:

heya dear....(◍•ᴗ•◍)

Explanation:

hope it helps....please to above pinned attachment...