Question

Solve this question.
It is very important.​

Answer 1

Answer:

Step-by-step explanation:

Given equation

(\sqrt[3]{3/5})^{2x+1}=125/27

then simplify the equation

\left ( 3/5 \right )^{(2x+1)/3}=\left ( 5/3 \right )^{3}

convert same base form \left ( a/b \right )^{m}=\left ( b/a \right )^{-m}

\left ( 3/5 \right )^{(2x+1)/3}=\left ( 3/5 \right )^{-3}

if base is same then compare the power and find out the value of x

\left ( 2x+1 \right )/3=-3

2x+1=-9

2x=-10

x=-5

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Answer 2

Step-by-step explanation:

Mark me as brainliest....