Solve this question. It's a 3 mark question. Detailed steps are needed
Attachments:
Answers
Answered by
0
Answer:
bhhbjoyghhgbxfhjjkkgjrfjhg
Answered by
0
Step-by-step explanation:
cosA/1-tanA-sin^2A/cosA-sinA=cosA+sinA
L.H.S.=cosA/1-tanA-sin^2A/cosA-sinA
=cosA/(1-sinA/cosA)-sin^2A/cosA-sinA
=cosA/(cosA-sinA/cosA)-sin^2A/cosA-sinA
=cos^2A/cosA-sinA-sin^2A/cosA-sinA
=cos^2A-sin^2A/cosA-sinA
=(cosA-sinA) (cosA+sinA)/cosA-sinA
=cosA+sinA
L.H.S.=R.H.S.
Similar questions