Question

solve this question

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Answer 1

Answer:

$7 ^{x} - 16y = 0 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 7 ^{x} = 16y \\ 4 ^{x} - 49y = 0 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 4^{x} = 49y$

$\frac{7 ^{x} }{4^{x} } = \frac{16y}{49y} \\ (\frac{7}{4} ) ^{x} = \frac{4^{2} }{7^{2} }$

$(\frac{7}{4} )^{x} = (\frac{4}{7} )^{2} \\ ( \frac{7}{4} ) ^{x} = ( \frac{7}{4} ) ^{ - 2}$

$x = - 2$

$y = \frac{ 7^{ - 2} }{16} \\ y = \frac{1}{49 \times 16} \\ y = \frac{1}{784}$

Now,

$y - x = \frac{1}{784} + 2 \\ y - x = \frac{1 + 1568}{784} \\ y - x = \frac{1569}{784}$

Answer 2

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