Math, asked by sonusharma45, 6 months ago

solve this question mate ​

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Answered by tennetiraj86
2

Answer:

\huge{\boxed{\rm{\red{a>0 (or)a≥1,a€N}}}}

Step-by-step explanation:

Given equation is 30 ax²-6x+1=0

On comparing this equation with the standard equation ax²+bx+c=0

we have a=30a; b=-6;c=1

If it has no real roots then the discriminant of the given equation must be less than zero.

The discriminant(d)=-4ac<0

=>(-6)²-4(30a)(1)<0

=>36-120a<0

If a=1 then 36-120(1)=36-120=-84<0

If a=2 then 36-120(2)=36-240=-204<0

So If a≥1 or a>0 then given equation has no real roots .

The possible values of a =1,2,3...

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