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Step-by-step explanation:
Given equation is 30 ax²-6x+1=0
On comparing this equation with the standard equation ax²+bx+c=0
we have a=30a; b=-6;c=1
If it has no real roots then the discriminant of the given equation must be less than zero.
The discriminant(d)=b²-4ac<0
=>(-6)²-4(30a)(1)<0
=>36-120a<0
If a=1 then 36-120(1)=36-120=-84<0
If a=2 then 36-120(2)=36-240=-204<0
So If a≥1 or a>0 then given equation has no real roots .
The possible values of a =1,2,3...
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