Question

solve this question mate ​

Answer 1

Step-by-step explanation:

Analysis:

AP= Arithmetic progression

We know that an arithmetic progression is a sequence of numbers such that the difference between the consecutive terms is constant. For instance, the sequence

5, 7, 9, 11, 13, 15, . . . is an arithmetic progression with a common difference of 2.

In an arithmetic progression, first term= a and common difference = d

second term= a+d

third term= a+2d and goes on

$Sum \: of \: an \: arithmetic \: progression = \frac{n}{2} (2a + (n - 1)d$

Information given:

12th term= -13

Sum of first 4 terms = 24

Therefore, a+11d= -13

=> a= -13-11d --------(1)

S₄=>

$24 = \frac{4}{2} (2 \times ( - 13 - 11d) + (4 - 1)d) \\ = > 24= 2(( - 26 - 22d) + 3d) \\ = > 24= 2( - 26 - 19d) \\ = > 12 = - 26 - 19d \\ = > 12 + 26 = - 19d \\ = > 38 = - 19d \\ = > d = - \frac{38}{19} \\ = > d = - 2$

Now, a= -13d-11

=> a= -13(-2)-11

=> a= 26-11

=> a= 15

Therefore, S₁₀=>

$\frac{10}{2} ((2 \times 15) + (10 - 1) - 2 )\\ = > 5((30) + (9 \times - 2)) \\ = > 5(30 - 18) \\ = > 5(12) \\ = > 60$

Therefore, sum of first 10 terms is 60

Hope its helpful~

Answer 2

Answer:

Sum of its first 10 terms is zero(0)