Question

solve this question mates​

Answer 1

Answer:

please mark as brain list I need it please

Step-by-step explanation:

Often, the simplest way to solve "ax2 + bx + c = 0" for the value of x is to factor the quadratic, set each factor equal to zero, and then solve each factor. But sometimes the quadratic is too messy, or it doesn't factor at all, or you just don't feel like factoring.

Answer 2

Step-by-step explanation:

Answer:

$\huge{\boxed{\rm{\red{a>0 (or)a≥1,a€N}}}}$

Step-by-step explanation:

Given equation is 30 ax²-6x+1=0

On comparing this equation with the standard equation ax²+bx+c=0

we have a=30a; b=-6;c=1

If it has no real roots then the discriminant of the given equation must be less than zero.

Thediscriminant(d)=b²-4ac<0

=>(-6)²-4(30a)(1)<0

=>36-120a<0

If a=1 then 36-120(1)=36-120=-84<0

If a=2 then 36-120(2)=36-240=-204<0

So If a≥1 or a>0

then given equation has no real roots .

The possible values of a =1,2,3...