Math, asked by smartykiller, 9 months ago

Solve this question:-

Mole fraction of CH3OH in mixture containing CH3OH and C2H5OH is 0.5. Hence mass percentage of CH3OH in the mixture is :

If u can't then Don't spam.

Answers

Answered by Anonymous

$<body bgcolor = "r"> <font color =pink>$

$\huge{\underline{\underline{\mathfrak{Answer}}}}$

As the mole fraction of CH3OH is 0.5 then two alcohols are in 1:1 molar ratio.

Molar mass of CH3OH = 32gmol^-1

Hence the mass % of CH3OH in the mixture

$<marquee> ᴍʀ ꜱʜᴀʀᴇᴇꜰ(｡♥‿♥｡)</marquee>$

Answered by Siddharta7

Answer:

41.025

Step-by-step explanation:

Given,

mole fraction of CH₃OH is 0.5

Molar mass of CH₃OH = 32 g/mol

Molar mass of C₂H₅OH = 46 g/mol

Now,

the mass% of CH₃OH in the mixture,

= (32/32 + 46) * 100

= 41.025

Hope it helps!

Previous Question

Next Question