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Answer:
AB = AB
AD = BC
AC = BD
∠DAB = ∠CBA
∠DBA = ∠CAB
∠ADB = ∠BCA
Step-by-step explanation:
We have,
ΔDAB and ΔCAB
Now,
In ΔDAB and ΔCAB,
∠DAB = 45° + 30° = 75°
∠CBA = 45° + 30° = 75°
So,
∠DAB = ∠CBA [Angle]
AB = AB [Common Side]
∠DBA = ∠CAB = 30° [Angle]
Hence,
ΔDAB ≅ ΔCBA (By A.S.A. Congruency)
So,
AB = AB
AD = BC
AC = BD
∠DAB = ∠CBA
∠DBA = ∠CAB
∠ADB = ∠BCA
Hope it helped and believing you understood it....All the best
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