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• Formula used :- ∫ xⁿ dx = xⁿ+¹/n+1 + C
∫ 1/x⅓ dx = ∫ x-⅓ dx
=> (x-⅓+¹) / 1-1/3 +C
=> (3x⅔)/2 + C
∫ 1/x⅓ dx = ∫ x-⅓ dx
=> (x-⅓+¹) / 1-1/3 +C
=> (3x⅔)/2 + C
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