Question

Solve this Question number 5

Answer 1

heya answer is here.............
it may be helps u dear.....

Answer 2

a+b+c=0
(a+b)sq/ab + (b+c)sq/bc + (c+a)sq/ca?

a+b= -c and b+c= -a and c+a= -b

(-c)2/ab + (-a)2/bc + (-b)2/ca
★c/ab + a/bc + b/ca
= c(bc)(ac) / ab.bc.ca + a(ac)(ab)/ab.bc.ca + b(ab)(bc)/ab.bc.ac
= ( abc3 + a3bc + ab3c ) / a2b2c2
= abc ( c2 + a2 + b2 ) / a2b2c2
=( a2 + b2 + c2 ) / abc


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