solve this question number 6 ..
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hope this will help you a lot
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Hello Mate!
In Triangle ABC,
Given : AB = AC, AD bisects angle BAC
To Prove : The bisector AD is perpendicular to BC.
Proof : In Triangle ABC
AB = AC ( Given )
AD = AD ( Common )
angle BAD = angle CAD
Hence both triangles are congruent by SAS theorum.
Now, Angle ADB = Angle ADC ( c.p.c.t )
Now, let angle ADB = x, then ADC will also be x
angle ( ADB + ADC ) = 180°
x + x =180°
2x = 180° or x = 180° / 2 = 90°
So angle ADB or ADC = 90°
Hence proved that AD is perpendicular at BC
Hope it helps☺!✌
In Triangle ABC,
Given : AB = AC, AD bisects angle BAC
To Prove : The bisector AD is perpendicular to BC.
Proof : In Triangle ABC
AB = AC ( Given )
AD = AD ( Common )
angle BAD = angle CAD
Hence both triangles are congruent by SAS theorum.
Now, Angle ADB = Angle ADC ( c.p.c.t )
Now, let angle ADB = x, then ADC will also be x
angle ( ADB + ADC ) = 180°
x + x =180°
2x = 180° or x = 180° / 2 = 90°
So angle ADB or ADC = 90°
Hence proved that AD is perpendicular at BC
Hope it helps☺!✌
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