Solve this question of electric field and flux
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As we learnt in Gauss's law,the total flux linked with Gaussian surface,
is,
ϕ=ϕE.ds=ε0Qenc
Where Qenc= total charge enclosed by a closed surface.
electric flux through ABCD=zero
for the change placed outside the box.
but for charge inside the case.
it ε09 throught all the surface,
so,
for one surface,6ε09
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