Solve this question only u know then Math
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REFER PIC PLEASE ABOVE....
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Answer :
f(x)=( - 3/4) x^4−8x^3- (45/2)x^2+105
f′(x)= - 3x^3 - 24x^2 - 45x
=−3x[x^2 +8x+15]
=−3x[x^2 +5x+3x+15]
=−3x[x(x+5)+3(x+5)]
=−3x(x+5)(x+3)
Now for critical points f′ (x)=0 gives
x=−5 and x=−3
∴at x=−5 is a point of minima
∴at x=−3 is a point of maxima.
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