Accountancy, asked by pallavitanna, 9 months ago

Solve this question only u know then Math​

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Answered by aadishree7667
5

REFER PIC PLEASE ABOVE....

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Answered by Anonymous
0

Answer :

f(x)=( - 3/4) x^4−8x^3- (45/2)x^2+105

f′(x)= - 3x^3 - 24x^2 - 45x

=−3x[x^2 +8x+15]

=−3x[x^2 +5x+3x+15]

=−3x[x(x+5)+3(x+5)]

=−3x(x+5)(x+3)

Now for critical points f′ (x)=0 gives

x=−5 and x=−3

∴at x=−5 is a point of minima

∴at x=−3 is a point of maxima.

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