CBSE BOARD X, asked by nsneebbej3, 11 months ago

solve this question pleaa​

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Answers

Answered by Anonymous
1

SEE THE AATACHMENT YOUR ANSWER IS THIS AND I THINK IT IS CORRECT

#TOGETHER WE GO FAR✔✔

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Answered by Anonymous
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Answer:

➻ 9 sec²A - 9 tan²A

[ Taking 9 Common ]

➻ 9 (sec²A - tan²A)

➻ 9 × 1 [sec²A - tan²A = 1]

➻ 9

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