Question

solve this question please​

Answer 1

SEE THE AATACHMENT YOUR ANSWER IS THIS AND I THINK IT IS CORRECT

#TOGETHER WE GO FAR✔✔

Answer 2

Answer:

As we are given a, b,c are in G.P lets assume, a=br; b=b; c=br

Where r→common ratio between the terms such that ratio of cb=ba

Now, we calculate value of a2 + b2, ab+ bc, b2 + c2 to prove that these are in G.P

1st term=a2 + b2=(br)2+b2=b2(1+r2)r2

2nd term ab+bc=br×b+b×br=b2(1+r2)r

3rd term b2 + c2=b2+b2r2=b2(1+r2)

3rdterm2ndterm=b2(1+r2)b2(1+r2)r=b2(1+r2)×rb2(1+r2)=r …(1)

2ndterm1stterm=b2(1+r2)r×r2b2(1+r2)=r …(2)

From eq (1) & (2)common ratios are same so a2 + b2, ab+ bc, b2 + c2 in G.P