Math, asked by eashaa, 1 year ago

Solve this question please​

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Answered by Anonymous
27

Given :-

6/√3 - 1/√2 + 10/√5

 \sf =   \left(\frac{6}{ \sqrt{3} } \times    \frac{ \sqrt{3} }{ \sqrt{3} }  \right) - \left(  \frac{1}{ \sqrt{2} }  \times  \frac{ \sqrt{2} }{ \sqrt{2} }  \right) +   \\  \\  \sf\left( \frac{10}{ \sqrt{5} }  \times  \frac{ \sqrt{5} }{ \sqrt{5} }  \right) \\  \\  \sf =  \frac{6 \sqrt{3} }{3}  -  \frac{1 \sqrt{2} }{2}  +  \frac{10 \sqrt{5} }{5}

Taking LCM of 3, 2 and 5 = 3 × 2 × 5 = 30

= (6√3 × 10)/(3 × 10) - (1√2 × 15)/(2 × 15) + (10√5 × 6)/(5 × 6)

= 60√3/30 - 15√2/30 + 60√5/30

= (60√3 - 15√2 + 60√5)/30

= 15(4√3 - √2 + 4√5)/30

= (4√3 - √2 + 4√5)/2

Answered by MarshmellowGirl
47

{\textbf{Answer}}

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