Question

Solve this question please

Answer 1

Answer:

the answer of this question is 3

Answer 2

Answer:

option (3) , option (4). IND.

Step-by-step explanation:

(I)here A,B,C,D & E each has 3 cards and there are 3 envelops of each (R,Y ,Br) and of each color there are 5 envelops.

means R -5 ,Y - 5 , Br - 5

(ii) R-5 => B,D,E , Y-5 => A,B,C

Br-5 => C,D,E

(iii) R - 5 => B-2 ,D -2 , E - 1

questions:

12.

Br-5 => E-2, C-2,D-1.

since there are 3 cards of E and 1 already put in R and Y can't take E cards So other 2 will be put in Br envelops.

here are 2 - E cards in Brown becoz of statement 3 where it is said that 2-B,2-B are in R envelops so R can take only 1 E to fill all 5 envelops so remaining 2 -E cards are put in Br envelops.

Answer: 2-E option (3) is correct

13.

Y -5 => 3 - A , B- 1, C- 1

option(4) is correct