Question

Solve this question please​

Answer 1

Answer:

The Height of the cable tower is 7(1-√3) m

Answer 2

Given :------

( First of all see image )

• AB = buliding = 7m
• BC = DE Base distance between tower and building.
• EC = x metre = Height of tower .
• angle ACB = 45°
• angle AED = 60°

Solution :-----

in ∆ABC first , we have ,

→ Tan 45° = AB /BC

→ 1 = 7m/BC

→ BC = 7m ..

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Now, since BC = DE = 7m .

in ∆ADE now,

→ tan60° = AD / DE

→ √3 = AD/7

→ AD = 7√3 m

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Now, From diagram we can see that,

Height of Tower = EC = BD = AB - AD

→ BD = (7 - 7√3) = 7(1-√3) metre ..

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Hence, Height of Tower will be 7(1-√3) metre ..

#BAL

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