Question

solve this question please.​

Answer 1

5......................

Answer 2

Let's solve your equation step-by-step.

$\sf \dfrac{2-9z}{17-4z} =\dfrac{4 }{5}$

Step 1: Cross-multiply.

⇒ $\sf \dfrac{2-9z}{17-4z} =\dfrac{4 }{5}$

⇒ $\sf (2- 9z)\times(5)=4\times (17-4z)$

⇒ $\sf -45z+10= -16z+68$

$\rule{300}{0.5}$

Step 2: Add 16z to both sides.

⇒ $\sf -45z+10+16z = -16z+68+16z$

⇒ $\sf -29z+10=68$

$\rule{300}{0.5}$

Step 3: Subtract 10 from both sides.

⇒ $\sf -29z+10-10=68-10$

⇒ $\sf -29z=58$

$\rule{300}{0.5}$

Step 4: Divide both sides by -29.

⇒ $\sf \dfrac{-29z}{-29} = \dfrac{58}{-29}$

⇒ $\sf z=-2$

$\rule{300}{0.5}$

Verification if z = -2

⇒ $\sf \dfrac{2-(9\times -2) }{17-(4\times -2) } =\dfrac{4 }{5}$

⇒ $\sf \dfrac{2-(-18) }{17-(-8) } =\dfrac{4 }{5}$

⇒ $\sf \dfrac{2+18 }{17+8 } =\dfrac{4 }{5}$

⇒ $\sf \dfrac{20}{25} =\dfrac{4}{5}$

⇒ $\sf \dfrac{20 \div 5 }{25 \div 5 } = \dfrac{4}{5}$

⇒ $\sf \dfrac{4}{5}=\dfrac{4}{5}$

$\rule{300}{0.5}$

$\sf \bf \therefore z=-2 \ in \ the \ equation \ => \dfrac{2-9z}{17-4z} =\dfrac{4 }{5}$