Question

Solve this Question!!

Please
☺​

Answer 1

Figure shows the Free Body Diagram of the bob when it's at mean position.

We get,

$\sf{\longrightarrow kl+\dfrac{mg}{2}=mg}$

$\sf{\longrightarrow kl=\dfrac{mg}{2}}$

$\sf{\longrightarrow\dfrac{m}{k}=\dfrac{2l}{g}}$

Here,

• $\sf{kl}$ is the force developed in the string due to strain.

• $\sf{mg}$ is weight of bob.

• $\sf{\dfrac{mg}{2}}$ is upthrust on the bob. Given that upthrust is half the weight of the bob.

Then time period will be,

$\sf{\longrightarrow T=2\pi\sqrt{\dfrac{m}{k}}}$

$\sf{\longrightarrow\underline{\underline{T=2\pi\sqrt{\dfrac{2l}{g}}}}}$

Answer 2

Answer:

here is ur ans...more simple one