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Equation => x² + px + v = 0
a = 1
-b = -p
c = v
Let alpha be 'A' and beta be 'B'
So,
A + B = -b/a = -p
AB = c/a = v
Now,
=> A/B + B/A
=> (A² + B²)/AB
=> [(A + B)² - 2AB]/AB
=> (p² - 2v)/v
So,
Ans:- Option (a) (p² - 2v)/v
Hope this helps...:)
Equation => x² + px + v = 0
a = 1
-b = -p
c = v
Let alpha be 'A' and beta be 'B'
So,
A + B = -b/a = -p
AB = c/a = v
Now,
=> A/B + B/A
=> (A² + B²)/AB
=> [(A + B)² - 2AB]/AB
=> (p² - 2v)/v
So,
Ans:- Option (a) (p² - 2v)/v
Hope this helps...:)
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