Question

solve this question please​

Answer 1

Given :

$\frac{ - 13}{20} + \frac{11}{14} + \frac{ - 5}{7} + \frac{7}{10}$

To find :

• Addition of them

Solution :

Solving First 2 fraction

$\frac{ - 13}{20} + \frac{11}{14} \\ \frac{( - 13 \times 14) + (20 \times 11)}{20 \times 14} \\ \frac{ - 182+ 220}{280} \\ \frac{38}{280} \\ \frac{19}{140}$

Solving Remaining 2 fraction

$\frac{ - 5}{7} + \frac{7}{10} \\ \frac{( - 5 \times 10) + (7 \times 7)}{7 \times 10} \\ \frac{ - 50 + 49}{70} \\ \frac{ - 1}{70}$

Adding both side

$\frac{19}{140} + \frac{ - 1}{70} \\ \frac{(19 \times 70) + (140 \times - 1)}{140 \times 70} \\ \frac{1330 - 140}{9800} \\ \frac{1190}{9800} \\ \frac{119}{980}$

Required more

$\frac{119}{980} = 0.12$

Answer is 0.12

Answer 2

- 13 / 20 + 11 / 14 + - 5 / 7 + 7 / 10

solution

- 13/20 + 11 / 14 + - 5/7 + 7 / 10

- 91/140 + 110/140 + - 5/7 + 7/10

- 91 + 110 / 140 + - 5/7 + 7 / 10

19 / 140 + - 5/7 + 7 / 10

19 / 140 - 5 / 7 + 7 / 10

19 / 140 - 100 / 140 + 7 / 10

19 - 100 / 140 + 7 / 10

- 81/140 + 7 / 10

- 81/140 + 98 / 140

- 81 + 98 / 140

17 / 140