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Here we have a right angled isosceles triangle as angle a = angle b
therefore AB = BC(sides opposite to equal angles are equal)
We know that in rright angled triangle, a²+b²=h²(pythagoras theorem)
AB² +BC²=AC²
AB = BC
so, AB²+AB²=AC²
2AB²=AC²
√2AB² = √AC² = AC
AB√2 = AC = 16√2
Now cancel √2 from both sides
AB = 16cm
Step-by-step explanation:
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