Question

solve this question please (5x*x+2x+1=7)

Answer 1

Hope u like my process
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Formula to be used.::
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Sreedhar Acharya's formula for any such equation like ax² + bx + c =0, is

$= > x = \frac{ - b + - \sqrt{ {b}^{2} - 4ac } }{2a}$
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Given::
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$= > \: \: 5 {x}^{2} + 2x + 1 = 7 \\ \\ or. \: \: 5 {x}^{2} + 2x + 1 - 7 = 0 \\ \\ or. \: \: 5 {x}^{2} + 2x - 6 = 0 \\ \\now \\ \\ applying \: sreedhar \: acharyas \: \: formula \\ \\ either \\ .......... \\ x = \frac{ - 2 + \sqrt{ {2}^{2} - 4 \times 5 \times ( - 6) } }{2 \times 5} \\ \\ \: \: \: \: = \frac{ - 2 + \sqrt{4 + 120} }{10} = \frac{ - 2 + \sqrt{124} }{10} \\ \\ \: \: \: \: = \frac{ - 2 + 11.135}{10} = \frac{9.135}{10} = 0.9135 \\ \\ else \\ ........ \\ x = \frac{ - 2 - \sqrt{ {2}^{2} - 4 \times 5 \times ( - 6) } }{2 \times 5} \\ \\ \: \: \: \: = \frac{ - 2 - \sqrt{124} }{10} = \frac{ - 2 - 11.135}{10} \\ \\ \: \: \: \: = \frac{ - 13.135}{10} = - 1.3135$
So,..

=> x = - 1.3135,, or,, 9.135

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