Question

solve this Question please

Answer 1

ANSWER


Let the numbers of G.P is


$= > \frac{a}{r} \: \: \: a \: \: \: ar$

product of these three term


$= \frac{a}{r} \ \times \: \: a \: \times \: ar \: \: = - 64$


$= > {a}^{3} = - 64$


$= > a = - 4$



so now find values of these terms


ACCORDING TO GIVEN CONDITION


( Value of ist term is four time the third)


$\frac{a}{r} = 4ar$

so,


$\frac{a}{ {r}^{2} \times a } = 4$


$\frac{1}{ {r}^{2} } = 4$

${r}^{2} = 4$


$r = 2$

so

a=-4

r=2

SO VALUE OF ALL TERMS ARE



$\frac{a}{r} = \frac{ - 4}{2} = - 2$



$a = - 4$


$ar = - 4 \times 2 = - 8$