Question

solve this question please​

Answer 1

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♦ Given That

$\dfrac{Y -2}{Y - 5} = \dfrac{Y + 3}{Y+ 5}$

♦ Solution

$\dfrac{Y -2}{Y - 5} = \dfrac{Y + 3}{Y+ 5}$

• By using cross multiplication

$\implies ( Y - 2 ) ( Y + 5 ) = ( Y + 3) ( Y - 5)$

$\implies Y^2 + 3Y - 10 = Y^2 -2Y - 15$

• By organization of terms

$\implies Y^2 - Y^2 + 3Y + 2Y = - 15 + 10$

$\implies (0) + 5 Y = - 5$

$\implies 5Y = - 5$

$\implies Y = \dfrac{-5}{5}$

$\implies Y = -1$

So , value of Y = -1

Checking

$\dfrac{Y -2}{Y - 5} = \dfrac{Y + 3}{Y+ 5}$

• Putting values of Y = -1

$\implies \dfrac{(-1) -2}{(-1) - 5} = \dfrac{(-1) + 3}{(-1)+ 5}$

$\implies \dfrac{-3}{-6} = \dfrac{2}{4}$

$\implies \dfrac{1}{2} = \dfrac{1}{2}$

Therefore As RHS = LHS , Hence Y = -1 satisfies the question .

Answer 2

HEY MATE ...



QUESTION SOLVE HO JAAYEGI....XD