Question

solve this question please ​

Answer 1

Answer:

Step-by-step explanation:

x/a-y/b=0

taking lcm ab

bx-ay/ab=0 eq1

ax+by7=a^2+b^2 eq2

Multiplying eq1 by a and eq2 by b we have

abx - a^2y=0

abx+b^2y=a^2b+b^3 (elimination method)

- - -

-a^2y-b^2y = -a^2b-b^3

y(-a^2-b^2)=b(-a^2-b^2)

y=b

put in eq1

bx-ay=0

bx-ab=0

bx=ab

x=a

x=a and y=b is the answer