Math, asked by ksjoei, 9 months ago

solve this question please help​

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Answered by Anonymous
5

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Answered by Anonymous
1

hy

here is your answer

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➡let the numbers be A AND 13/6-A=(13-6A)/6

➡LET 2N MEANS BE INSERTED

➡SUM OF THE 2N+2 TERMS =(NUMBER OF TERMS/2)(FIRST TERM+LAST TERM)=

{(2N+2)/2}{13/6}=13(N+1)/6

➡SUM OF 2N MEANS = SUM OF 2N+2 TERMS - SUM OF FIRST & LAST TERMS

= 13(N+1)/6 - 13/6 = 13N/6

➡THIS IS MORE THAN THEIR NUMBER 2N BY 1 = 2N+1

➡13N/6 = 2N+1

➡13N=12N+6

➡N=6

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