Question

solve this question please I will fo.l.low u​

Answer 1

Step-by-step explanation:

3x-2 is a factor means 2/3 is a zero of the equation

So let's assume that 2/3 is a zero of this equation

$3 {x}^{3} + {x}^{2} - 20x + 12$

if after putting the value of 2/3 it becomes zero then we will consider that our assumption is right other wise not

$3 ({ \frac{2}{3} })^{3} + ( \frac{2}{3})^{2} - 20 \times \frac{2}{3} + 12 \\ \frac{8}{9} + \frac{4}{9} - \frac{40}{3} + 12 \\ = 12 + \frac{12}{9} - \frac{40}{3} \\ = 12 - 12 = 0$

so we can say that (3x-2) is a factor of this equation.

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