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Answer:
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4). Solution:
We have ;
=> 2(a - 5) = 18
=> a - 5 = 18/2
=> a - 5 = 9
=> a = 9 + 5
=> a = 14
Hence,
The required value of a is 14 .
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5). Solution:
We have ;
=> 0.4 = y/25 + y
=> 0.4 = (y + 25y)/25
=> 0.4 = 26y/25
=> 26y/25 = 0.4
=> y = 0.4×25/26
=> y = 10/26
=> y = 5/13
Hence,
The required value of y is 5/13 .
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6). Solution:
We have ;
(3x + 4)/(2x + 4) = 4/3
On cross-multiplication , we have ;
=> 3(3x + 4) = 4(2x + 4)
=> 9x + 12 = 8x + 16
=> 9x - 8x = 16 - 12
=> x = 4
Hence,
The required value of x is 4 .
Verification:
=> LHS = (3x + 4)/(2x + 4)
=> LHS = (3•4 + 4)/(2•4 + 4)
=> LHS = (12 + 4)/(8 + 4)
=> LHS = 16/12
=> LHS = 4/3
=> LHS = RHS
Hence verified .
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7). Solution:
We have ;
(9x + 5)/2x = 15/2
On cross-multiplication , we have ;
=> 2(9x + 5) = 15•2x
=> 18x + 10 = 30x
=> 18x - 30x = -10
=> - 12x = -10
=> x = -10/-12
=> x = 5/6
Hence,
The required value of x is 5/6 .
Verification:
=> LHS = (9x + 5)/2x
=> LHS = (9•5/6 + 5)/(2•5/6)
=> LHS = (15/2 + 5)/(5/3)
=> LHS = [ (15 + 10)/2 ] / (5/3)
=> LHS = (25/2)/(5/3)
=> LHS = (25/2)×(3/5)
=> LHS = (25×3)/(2×5)
=> LHS = 5×3/2
=> LHS = 15/2
=> LHS = RHS
Hence verified .