Question

solve this question please
$prove \: that\: \: { \sin( - x) }^{ - 1} = - { \sin(x) }^{ - 1} \: \:$
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Answer 1

Answer:

1/a-n=a-n

Step-by-step explanation:

so the equation

Answer 2

$\huge\underline\bold\red{★Answer★}$

$let \: \: {sin}^{ - 1} ( - x) = y \\ \implies - x = siny \\ \implies x = - siny \\ \: \: \implies x = sin( - y) \\ hence \: \: \: {sin}^{ - 1} x = - y \\ \implies {sin}^{ - 1}x = - {sin}^{ - 1} ( - x) \\ \therefore \: \: \: {sin}^{ - 1} ( - x) = - {sin}^{ - 1} x$