Question

solve this question please with process

Answer 1

$\frac{1}{(x+2)(x+3)} = \frac{A}{x+2} + \frac{B}{x+3}$

Multiply both sides by denominator
$1=A(x+3)+B(x+2)$

The unreal roots are x=-3,-2
Substitute the roots
$For x=-3 , B=-1$
$For x=-2, A=1$

Therefore, $\frac{1}{(x+2)(x+3)} = \frac{1}{x+2}- \frac{1}{x+3}$