solve this question pleaseee. if anyone solve this issue I really mark him or her as brainliest
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1. 4a^2 + b^2 + 4ab
2. a^2 + 1/4a^2 + 1
3. a^2 + (b-c)^2 + 2a (b-c)
4. 9x^2 + 1/9x^2 + 2
2. a^2 + 1/4a^2 + 1
3. a^2 + (b-c)^2 + 2a (b-c)
4. 9x^2 + 1/9x^2 + 2
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Hi dear !
Identity used : -
(a + b)² = a² + b² + 2ab
(a + b + c) ² = a² + b² + c² + 2ab + 2bc + 2ac
i) (2a + b)² = (2a)² + b² + 2 (2a)(b) = 4a² + b² + 4ab
iii) (a + 1/a)² = a² + 1/a² + 2 (a) (1/a) = a² + 1/a² + 2
v) ( a + b - c) ² = a² + b² + (-c)² + 2(a)(b) + 2(b)(-c) + 2(-c)(a)
= a² + b² + c² + 2ab - 2bc - 2ac
vii) ( 3x + 1/3x)² = (3x)² + (1/3x)² + 2(3x)(1/3x)
= 9x² + 1/9x² + 2
Identity used : -
(a + b)² = a² + b² + 2ab
(a + b + c) ² = a² + b² + c² + 2ab + 2bc + 2ac
i) (2a + b)² = (2a)² + b² + 2 (2a)(b) = 4a² + b² + 4ab
iii) (a + 1/a)² = a² + 1/a² + 2 (a) (1/a) = a² + 1/a² + 2
v) ( a + b - c) ² = a² + b² + (-c)² + 2(a)(b) + 2(b)(-c) + 2(-c)(a)
= a² + b² + c² + 2ab - 2bc - 2ac
vii) ( 3x + 1/3x)² = (3x)² + (1/3x)² + 2(3x)(1/3x)
= 9x² + 1/9x² + 2
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