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The answer
The line AB II CE
Hence the alternate angles will be equal
Angle Q= 32
Let's find Angle P
Sum of all angles 180
Angle
angle B + Angle q + angle p
P = 58
Now in a Triangle the entire sum is 180
Angle q + Angle p + the angle = 180
180 - 90 = x
x = 90
r = 90
anglea in linear pair
The answer
The line AB II CE
Hence the alternate angles will be equal
Angle Q= 32
Let's find Angle P
Sum of all angles 180
Angle
angle B + Angle q + angle p
P = 58
Now in a Triangle the entire sum is 180
Angle q + Angle p + the angle = 180
180 - 90 = x
x = 90
r = 90
anglea in linear pair
Gamer007:
u r wrong..at q=32°...line BC and line AE are not parallel
angle p = angle ACE..... because line AB and line CE are parallel
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