Question

Solve this question pls

Answer 1

$= > 2( \frac{2x - 1}{x + 3} ) - 3( \frac{x + 3}{2x - 1} ) = 5$


$= > \frac{2(2x - 1)}{x + 3} - \frac{3(x + 3)}{2x - 1} = 5 \\ \\ \\ \\ = > \frac{2 {(2x - 1)}^{2} - 3 {(x + 3)}^{2} }{(x + 3)(2x - 1)} = 5 \\ \\ \\ \\ = > \frac{2(4 {x}^{2} + 1 - 4x) - 3( {x}^{2} + 9 + 6x)}{2 {x}^{2} - x + 6x - 3 } = 5 \\ \\ \\ \\ = > \frac{8 {x}^{2} + 2 - 8x - 3 {x}^{2} - 27 - 18x }{2 {x}^{2} + 5x - 3 } = 5 \\ \\ \\ \\ = > \frac{5 {x}^{2} - 26x - 25}{2 {x}^{2} + 5x - 3} = 5$


= > 5x² - 26x - 25 = 5( 2x² + 5x - 3 )


= > 5x² - 26x - 25 = 10x² + 25x - 15


= > 0 = 10x² - 5x² + 25x + 26x - 15 + 25


= > 0 = 5x² + 51x + 10


= > 0 = 5x² + ( 50 + 1 )x + 10


= > 0 = 5x² + 50x + x + 10


= > 0 = 5x( x + 10 ) + ( x + 10 )


= > 0 = ( x + 10 ) ( 5x + 1 )


= > x = - 10 or x = - 1 / 5