Question

solve this question plss need step by step explanation please don't answer if you don't know the solution (brainly teachers ain't good at solving questions, & sorry I can't judge them all m saying about that I hav met some r quite noobs)​

Answer 1

Question :-Find the equations of tangent and normal to the curve xy = 10 at (2,5).

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Equation of tangent is given by = (y-y1)= M(x-x1)

M=dy/dx of the curve

xy=10

y=10/x

dy/dx = (-10/x^2 ) at x = 2

M= -10/4=-5/2 so we get the slope now

y1=5 x1 =2

y-y1=m(x-x1) be equation of tangent

y-5=-5/2(x-2)

y+5/2x -10 = 0

2y + 5x - 20 =0 is the equation of tangent

now for equation of normal

we need Mn by using this equation

M*Mn = -1

Mn *-5/2 =-1

Mn =2/5 for equation of tangent

y-y1 =Mn (x-x1)

y-5 = 2/5(x-2)

y-2/5 x -5 + 4/5 = 0

5y - 2x -21 = 0 be the equation of tangent