Question

solve this question plz 105

Answer 1

(a+b+c)2=a2+ b2+ c2+2(ab+bc+ca)
(a+b+c)2=280+2*9/2
(a+b+c)2=289
(a+b+c)=√289
(a+b+c)=17

(a + b + c)3 = a3+ b3 +c3 + 3(a+b)(b+c)(c+a).
Or
(a + b + c)3 = (a+b+c)2*(a+b+c).
(a+b+c)3 = a2+ b2+ c2+2(ab+bc+ca)*(a+b+c)
(a+b+c)3=280+2*9/2*(a+b+c)
(a+b+c)3=280+9*(a+b+c)
(a+b+c)3=280+9*17
(a+b+c)3=289*17
(a+b+c)3=4913
Hope it helps
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