Physics, asked by jinnal3289, 11 months ago

solve this question plz.........​

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Answered by missShelly
61

❤ḙ!ժ Պṳ♭ᾰԻᾰк .❤

energy of incident Photon,

E = hc/ lemda

= 1242 eV nm/ 300nm

= 4.14 eV

electron will be knocked out of the hydrogen atom if:-

E > 13.6 eV

electron will go to First excited state if :-

E > 10.2 eV

so only electron will keep orbiting in the ground state of the atom.

тℏᾰℵкṧ

Answered by 45mehul
11

referred to above attachment please ....

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