Question

solve this question..............plz​

Answer 1

Answer:

1 : 1

Explanation:

let the mass of the 1st part be m

and the mass of the 1st part be M-m

F = Gm(M-m)/d²

F' =dF/dm = G(M-2m)/d² = 0

m = M/2

the ratio of masses =  M/2 :  M/2 = 1 : 1

Answer 2

(¯`·.¸¸.·´¯`·.¸¸.-> Solution <-.¸¸.·´¯`·.¸¸.·´¯)

Let the mass of the block is M

Mass of one part is m

Mass of another is M-m

Force between the Blocks

F = G(m)(M-m)/d²

F = GMm/d² - Gm²/d²....(1)

For F to be max df/dm has to zero

Differentiate (1) with respect to m

dF/dm = GM/d² d(m)/dm - {G/d²}d(m²)/dm

dF/dm = GM/d²(1) - {G/d²}(2m)

put df/dm=0

0 = GM/d²(1) - {G/d²}(2m)

0 = Gd²(M - 2m)

M = 2m

Hence ratio of both masses....M-m/m

2m-m/m = 1 : 1

#answerwithquality

#Bal