Question

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Answer 1

might help you.......if it helps please mark it as brainliest answer

Answer 2

❏ Question:-

@ Find the value of x ,

$\sf\longrightarrow x - \frac{x - 1}{2} = 1 - \frac{x - 2}{3}$

❏ Solution:-

: $\sf\implies x - \dfrac{x - 1}{2} = 1 - \dfrac{x - 2}{3}$

: $\sf\implies x - \dfrac{x - 1}{2} = 1 - \dfrac{x - 2}{3}$

: $\sf\implies\dfrac{2x - (x - 1)}{2} = \dfrac{3 - (x - 2)}{3}$

: $\sf\implies\dfrac{2x - x + 1}{2} = \dfrac{3 - x + 2}{3}$

: $\sf\implies\dfrac{x + 1}{2} = \dfrac{5 - x}{3}$

: $\sf\implies3\times(x + 1) = 2\times(5 - x)$

: $\sf\implies3x + 3 = 10 - 2x$

: $\sf\implies3x + 2x = 10 - 3$

: $\sf\implies5x = 7$

: $\sf\implies \boxed{\red{\large{x = \dfrac{7}{5}}}}$

∴ The value of x = $\sf \dfrac{7}{5}$