Question

solve this question plz.....

Answer 1

Let those terms be
$\frac{a}{r} \: and \: a \: and \: ar$
Given product =1000
i.e. a^3 = 1000
Therefore a = 10
Given sum = 35
Therefore
$\frac{10}{r} + 10 + 10r = 35 \\ \frac{10}{r} + 10r = 25 \\ \frac{1}{r} + r = \frac{5}{2} \\2 {r}^{2} - 5r + 2 = 0 \\ 2 {r}^{2} - 4r - r + 2 = 0 \\ 2r(r - 2) - 1(r - 2) = 0 \\ (r - 2)(2r - 1) = 0 \\r = 2 \: or \frac{1}{2}$
Therefore numbers can be
5,10 and 20
or
20,10 and 5.
Hope this helps.