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|a² (b²+c²) bc|
|b² (c²+a²) ca|
|c² (a²+b²). ab|
C2→C1+C2, taking a²+b²+c² common from C2
|a² 1. bc| ×(a²+b²+c²)
|b² 1. ca|
|c² 1. ab|
R1→R1-R2 and R2→R2-R3. And using the formula a²-b²=(a+b)(a-b)
|(a-b)(a+b). 0 c(b-a)| ×(a²+b²+c²)
|(b-c)(b+c). 0. a(c-b)|
|c² 1. ab|
Taking a-b and b-c common from R1 and R2
(A-b)(b-c)(a²+b²+c²)×
|(a+b . 0. -c|
|(b+c). 0. -a|
|c² 1. ab|
Expanding wrt to c2
=(a-b)(b-c)(a²+b²+c²){-1(-a²-ba+bc+c²)}
=(a-b)(b-c)(a²+b²+c²){(a²-c²)+b(a-c)}
=(a-b)(b-c)(a²+b²+c²)(a-c)(a+b+c)
|b² (c²+a²) ca|
|c² (a²+b²). ab|
C2→C1+C2, taking a²+b²+c² common from C2
|a² 1. bc| ×(a²+b²+c²)
|b² 1. ca|
|c² 1. ab|
R1→R1-R2 and R2→R2-R3. And using the formula a²-b²=(a+b)(a-b)
|(a-b)(a+b). 0 c(b-a)| ×(a²+b²+c²)
|(b-c)(b+c). 0. a(c-b)|
|c² 1. ab|
Taking a-b and b-c common from R1 and R2
(A-b)(b-c)(a²+b²+c²)×
|(a+b . 0. -c|
|(b+c). 0. -a|
|c² 1. ab|
Expanding wrt to c2
=(a-b)(b-c)(a²+b²+c²){-1(-a²-ba+bc+c²)}
=(a-b)(b-c)(a²+b²+c²){(a²-c²)+b(a-c)}
=(a-b)(b-c)(a²+b²+c²)(a-c)(a+b+c)
shashanksingh7:
tnxxx
Your welcome :)
bahut time laga hoga type karne me
Haan.
to copy pe likh ke pic send kr diya kijiye jaldi hoga
Haan. Par pas main pen nahi thi.
okk
(My Hindi is really bad :/
and once again thank you
Its okay
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I am attaching the pic of the solution.
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