Question

solve this question plz

Answer 1

|a² (b²+c²) bc|
|b² (c²+a²) ca|
|c² (a²+b²). ab|

C2→C1+C2, taking a²+b²+c² common from C2
|a² 1. bc| ×(a²+b²+c²)
|b² 1. ca|
|c² 1. ab|

R1→R1-R2 and R2→R2-R3. And using the formula a²-b²=(a+b)(a-b)
|(a-b)(a+b). 0 c(b-a)| ×(a²+b²+c²)
|(b-c)(b+c). 0. a(c-b)|
|c² 1. ab|

Taking a-b and b-c common from R1 and R2
(A-b)(b-c)(a²+b²+c²)×
|(a+b . 0. -c|
|(b+c). 0. -a|
|c² 1. ab|
Expanding wrt to c2
=(a-b)(b-c)(a²+b²+c²){-1(-a²-ba+bc+c²)}
=(a-b)(b-c)(a²+b²+c²){(a²-c²)+b(a-c)}

=(a-b)(b-c)(a²+b²+c²)(a-c)(a+b+c)

Answer 2

I am attaching the pic of the solution.