Question

Solve this question plz...​

Answer 1

Answer:

high gjb for the delay getting back camera

Answer 2

Answer:

$y=2 sin^{2} \theta+tan\theta$

$\frac{dy}{d\theta} = 2.\frac{d}{d\theta}(sin^{2} \theta)+\frac{d}{d\theta}( tan\theta)$

$\frac{dy}{d\theta} =2(2sin\theta.cos\theta)+sec^{2} \theta$

$\frac{dy}{d\theta} =2sin2 \theta+sec^{2} \theta$