Question

Solve this question plz

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Answer 1

Answer:

2x² + Kx + 3 = 0

a=2

b=k

c=3

b²-4ac = 0

k² - 24 = 0

k = √24

Kx(x-2)+6 =0

kx² - 2kx + 6 =0

b²-4ac = 4k² - 24k

4k² - 24k= 0

4k² = 24k

Answer 2

Answer:

2x^2+Rx+3=0

comparing equation with ax^2+bx+c=0

a=2,b=R.c=3

formula b^2-4ac=0

b^2-4ac=0

=(R)^2 -4×2×3=0

=R^2-24

=R^2=24

=R=+√24

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ans+ √24

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