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Initial speed of a jeep, u = 0
Time, t= 5.21 s
Distance, d = 110 m
To find,
The acceleration of the jeep.
Solution,
To find the acceleration, in this case,
use second
d = ut +
1
Put all values, we get :
d=
1
2
at²
2d
a=
2 x 110
(5.21)²
a=
a=
8.1 m/s²
So, the acceleration of the jeep is
8.1 m/s²
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