solve this question plz i am stuck at this
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Step-by-step explanation:
To solve this kind of question; 32^(x-2) = 64 + 8^x
Introduce a log to each value as follows,
log 32^(x-2) = log 64 + log 8^x
As we know when a log function has a power, the power comes in front of the function as follows
(x-2) log 32 - x log 8 = log 64
Sorry I don't have my calculator right now but I'll edit this after I find it
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