Question

Solve this question plz. I will make brainiest . Find the value of X.​

Answer 1

(2^2x-2 +10) ÷ 13 = 2

(2^2x -2 +10 ) = 26

2^2x-2 = 16

2^4 = 16

2x -2 = 4

2x = 6

x= 3

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Answer 2

Hey, here is your answer... ☺️ ❤️

$( {2}^{2x - 2} + 10) \div 13 = 2 \\ \\ ( {2}^{2x - 2} + 10) = 2 \times 13 = 26 \\ \\ ({2}^{2x - 2} + 10) = 26 \\ \\ {2}^{2x - 2} = 26 - 10 = 16 \\ \\ ({2}^{2x})( {2}^{ - 2}) = 16 \\ \\ ({2}^{2x} \div {2}^{2} ) = 16 \\ \\ ( {2}^{2x} \div 4) = 16 \\ \\ ({2}^{2x}) = 16 \times 4 \\ \\ {2}^{2x} = 64 \\ \\ {2}^{2x} = {2}^{6} \\ \\ since, \: bases \: are \: equal, \\ \:powers \: need \: to \: be \: equal \\\\ i.e., \: 2x = 6 \\ \\ x = (6 \div 2) \\ \\ = > x = 3$

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